For the reaction, `AB(g)hArr A(g)+B(g), AB" is "33%` dissociated at a total pressure of 'p' Therefore, 'p' is related to `K_(p)` by one of the following options

Options

A. `P=K_p`
B. `P = 3K_p`
C. `P = 4K_p`
D. `P =8K_p`

Answer

D

Explanation

`AB_((g)) hArrA_((g)) +B_((g))`
`{:("Initial moles",1,0,0),("Moles at eqm.",1-0.33, 0.33 ,0.33):}`
`p_A = ((0.33)/(1.33))P,p_B((0.33)/(1.33))P`
`p_(AB) = ((0.66)/(1.33))P`
`K_p = (p_A xxp_B)/(P_(AB))impliesK_p= (0.33 xx0.33 xxP)/(0.66xx1.33)`
`P/K_P=8impliesP=8K_p`