The equilibrium constant `K_(p_(1))` and `K_(p_(2))` for the reactions `XhArr2Y` and `ZhArrP+Q`, respectively are in the ratio of `1:9`. If the degree of dissociation of `X` and `Z` be equal, then the ratio of total pressure at these equilibrium is:

Options

A. `1:1`
B. `1:3`
C. `1:9`
D. `1:36`

Answer

D

Explanation

`X hArr 2Y " " Z hArr P + Q`
`{:("Ionic",1,0,"Ionic",1,0,0),("At eqm.",1-x,2x,"eqm.",1-x,x,x):}`
`K_(P_1)=(((2x)/(1+x)xxp_1)^2)/(((1-x)/(1+x)xxp_1))`
`K_(p_2)=((x^2p_2^2)/((1+x)^2))/(((1-x))/((1+x))xxp_2)`
`K_(p1)=(4x^2p_1)/(1-x^2)" "K_(p2)=(x^2P_2)/((1-x^2))`
`1/9=(K_(p_1))/(K_(p_2))=(4p_1)/(p_2),p_1/p_2=1/36`