In a chemical equilibrium `A + B hArr` C + D, when one mole each of the two reactants are mixed, `0.6` mole each of the products are formed. The equilibrium constant calculated is

Options

A. 1
B. 0.36
C. 2.25
D. `4//9`

Answer

C

Explanation

`A+B hArr C+D`
`{:("Initial",1,1,0,0),("remaining at equilibrium",0.4,0.4,0.6,0.6):}`
`K=([C][D])/([A][B])=(0.6 xx0.6)/(0.4 xx0.4)=36/16 = 2.25`