In a 500 ml capacity vessel CO and `Cl_(2)` are mixed to form `COCl_(2)`. At equilibrium, it contains 0.2 moles of `COCl_(2)` and 0.1 mole of each of CO and `Cl_(2)`. The equilibrium constant `K_(c)` for the reaction `CO+Cl_(2) hArr COCl_(2)` is

Options

A. 5
B. 10
C. 15
D. 20

Answer

B

Explanation

`CO+Cl_(2) hArr COCl_2`
`[CO]=(0.1)/(0.5),[Cl_2] = (0.1)/(0.5),[COCl_2]=(0.2)/(0.5)`
`=([COCl_2])/([CO][Cl_2])=((0.2)/(0.5))/((0.1)/(0.5)xx(0.1)/(0.5))=2/5 xx25 =10`