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The rate constant for forward and backwa...

The rate constant for forward and backward reactions of hydrolysis of ester are `1.1xx10^(-2)` and `1.5xx10^(-3)` per minute respectively. Equilibrium constant for the reaction is

A

4.33

B

5.33

C

6.33

D

7.33

Text Solution

Verified by Experts

The correct Answer is:
D
`K_f = K_f/(K_(b)) = (1.1 xx10^(-2))/(1.5 xx10^(-3))=7.33`
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