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The equilibrium constant (K(c)) for the ...

The equilibrium constant `(K_(c))` for the reaction HA + B `hArrBH^(+) + A^(-)` is 100. If the rate constant for the forward reaction is `10^(5)`, then constant for the backward reaction is

A

`10^7`

B

`10^3`

C

`10^(-3)`

D

`10^(-5)`

Text Solution

Verified by Experts

The correct Answer is:
B
`K_c =K_f/K_(b), :. K_b = K_f/K_(c)=10^5/100 =10^3`
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