Given that equilibrium constant for the reaction `2SO_(2)(g) + O_(2)(g)hArr2SO_(3)(g)` has a value of 278 at a particular temperature. What is the value of the equilibrium constant for the following reaction at the same temperature ? `SO_(3)(g)hArrSO_(2)(g) + (1)/(2)O_(2)(g)`

Options

A. `1.8xx10^(-3)`
B. `3.6xx10^(-3)`
C. `6.0xx10^(-2)`
D. `1.3xx10^(-5)`

Answer

C

Explanation

`2SO_(2) (g) +O_(2) (g) hArr2SO_(3)(g)`
`SO_(3) (g) hArrSO_(2)(g)+1/2O_(2)(g)`
`K = 278`
`K.=1/K = sqrt(1/(278))=sqrt(35.97 xx10^(-4))=6xx10^(-2)`