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The following equilibria are given by : ...

The following equilibria are given by `:`
`N_(2)+3H_(2) hArr 2NH_(3), K_(1)`
`N_(2)+O_(2) hArr 2NO,K_(2)`
`H_(2)+(1)/(2)O_(2) hArr H_(2)O, K_(3)`
The equilibrium constant of the reaction `2NH_(3)+(5)/(2)O_(2)hArr 2NO +3H_(2)O` in terms of `K_(1) , K_(2)` and `K_(3)` is

A

`(K_2K_3^3)/K_1`

B

`K_1K_2K_3`

C

`(K_1K_2)/K_3`

D

`(K_1K_3^2)/K_2`

Text Solution

Verified by Experts

The correct Answer is:
A
`2NH_3 hArrN_(2) +3H_(2) K. =1/(K_1)`
`N_(2) +O_(2) hArr 2NO " " K.. = K_2`
`(3H_2+3/2O_2hArr3H_2OK..=(K_3)^3)/(2NH_3+5/2O_2hArr2NO+3H_2O)`
`:.` for the given reaction
`K = K. xxK. xx K..`
`K=1/K_1 xxK_2 xx(K_3)^3 = (K_2(K_3)^3)/(K_1)`
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