If the concentration of `OH^(-)` ions in the reaction
`Fe(OH)_(3)(s)hArrFe^(3+)(aq.)+3OH^(-)(aq.)`
is decreased by `1//4` times, then the equilibrium concentration of `Fe^(3+)` will increase by

Options

A. 64 times
B. 4 times
C. 8 times
D. 16 times

Answer

A

Explanation

`Fe(OH)_(3) (s) hArr Fe^(3+) (aq). +3OH^(-) (aq)`
`K = [Fe^(3+)][OH^(-)]^(3)`
If the concentration of `OH^(-)` decreased by 1 / 4 times then the concentration of `Fe^(3+)` will increase by `4^3 = 64` times.