28 g of `N_(2)` and 6 g of `H_(2)` were kept at `400^(@)C` in 1 litre vessel, the equilibrium mixture contained `27.54` g of `NH_(3)`. The approximate value of `K_(c)` for the above reaction can be `("in mole"^(-2) "litre"^(2))`

Options

A. 75
B. 50
C. 25
D. 100

Answer

A

Explanation

`N_2 +3H_2 hArr 2NH_3`
`{:("Initial conc.",1,3,0),("at equilibrium",1–0.81, 3–2.43 ,1.62),(,0.19,0.57,):}`
No. of moles of `N_2 = 28/28 =1` mole
No. of moles of `H_2 = 6/2 =3` mole
No. of moles of `NH_3 = (27.54)/17 = 1.62` mole
`K_c=([NH_3]^2)/([N_2][H_2]^3)=([1.62]^2)/([0.19][0.57]^3)= 75`