For the reaction `H_(2)(g) + I_(2)(g)hArr2HI(g)` at 721 K the value of equilibrium constant `(K_(c))` is 50. When the equilibrium concentration of both is `0.5` M, the value of `K_(p)` under the same condtions will be

Options

A. `0.002`
B. `0.2`
C. 50
D. 50/RT

Answer

C

Explanation

For the reaction `H_2 + I_2 hArr 2HI`
`Deltan =0`
So `K_p = K_c :. 50`