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For a given exothermic reaction , K(p) a...

For a given exothermic reaction , `K_(p)` and `k'_(p)` are the equilibrium constants at temperatures `T_(1)` and `T_(2)` respectively. Assuming that heat of reaction is constant in temperature range between `T_(1) and T_(2)` , it is readily observed that

A

`K_p = K'_p`

B

`K_p =1/(K'_p)`

C

`K_p gt K'_p`

D

`K_p lt K'_p`

Text Solution

Verified by Experts

The correct Answer is:
C
In exothermic reaction on increasing temperature, value of `K_p` decreases So , `K_p gt K_p`
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