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The chemical reaction : BaO(2(s))hArrBaO...

The chemical reaction : `BaO_(2(s))hArrBaO_((s))+1/2O_(2(g)),DeltaH=+ve.` In equilibrium condition, pressure of `O_(2)` depends upon

A

`DeltaH=+ve`. In equilibrium condition, pressure of `O_2` depends upon

B

Increase mass of Bao

C

Increase mass of `BaO_2`

D

Increase in temperature

Text Solution

Verified by Experts

The correct Answer is:
C
`BaO_(2)(s) hArr BaO(s) +(1)/2 O_(2)(g)`
`K_p =[PO_2]^(1//2)`
On increase of temperature reaction will move in forward direction which will increase the pressure of `O_2` gas.
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