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When KMnO(4) is reduced with oxalic acid...

When `KMnO_(4)` is reduced with oxalic acid in acidic solution, the oxidation number of `Mn` changes from

A

7 to 4

B

6 to 4

C

7 to 2

D

4 to 2

Text Solution

Verified by Experts

The correct Answer is:
C
`5underset(COOH)overset(COOH)(|)+overset(+7)(2KMnO_4)+3H_2SO_4 rarrK_2SO_4+overset(+2)(2MnSO_4)+10CO_2+8H_2O`
In this reaction oxidation state of Mn change from + 7 to + 2.
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