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The oxidation states of the most electro...

The oxidation states of the most electronegative element in the products of the reaction between `BaO_2` with dilute `H_2SO_4` are

A

0 and – 1

B

`-1` and - 2

C

`-2` and 0

D

`-2` and 1

Text Solution

Verified by Experts

The correct Answer is:
B
In `H_2O_2` oxygen shows = - 1 (peroxide) oxidation state and in `BaSO_4` oxygen shows = – 2 oxidation state.
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