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Maximum number of moles of electrons tak...

Maximum number of moles of electrons taken up by one mole of `NO_(3)^(-)` when it is reduced to :

A

`NH_3`

B

`NH_2OH`

C

NO

D

`NO_2`

Text Solution

Verified by Experts

The correct Answer is:
A
Oxidation no. of N in `NO_3^(-) =+5`
`NH_3=-3 , NH_2 OH =-1 , NO =+2 , NO_2 =+4`
So one mole of `NO_3^(-)` will require maximum no. of moles of electron by reducing into `NH_3{5-(-3)=8}`
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ERRORLESS-REDOX REACTIONS-NCERT BASED QUESTION (Oxidizing and Reducing Agent)
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