H(2)S acts only as reducing agent while ...

`H_(2)S` acts only as reducing agent while `SO_(2)` can act both as a reducing agent and as an oxidising agent. How will you account for it ?

S in `H_2S` has - 2 oxidation state

S in `SO_2` has oxidation state + 4

Hydrogen in `H_2S` more +ve than oxygen

Oxygen is more – ve in `SO_2`

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Verified by Experts

The correct Answer is:

A, B

In `H_2S` sulphur shows – 2 oxidation state and in `SO_2` shows + 4 oxidation state. Hence `SO_2` shows both oxidising and reducing properties.

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