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In the reaction, I(2)+2S(2)O(3)^(2-) r...

In the reaction,
`I_(2)+2S_(2)O_(3)^(2-) rarr 2I^(-)+S_(4)O_(6)^(2-)`.
Equivalent wieght of iodine will be equal to

A

1/2 of molecular weight

B

Molecular weight

C

1/4 of molecular weight

D

None

Text Solution

Verified by Experts

The correct Answer is:
A
`overset((0))(I_2)+2S_2O_3^(2-)rarroverset((-1))(2l^(-))+S_4O_6^(2-)`
Equivalent weight of iodine = `("Molecular wt.")/("Total change in O.N.")`
`= ("Molecular weight")/(2 xx{0-(-1)}) = ("Molecular weight")/2`
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