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In the disproportionation 3HClO(3)rarrHC...

In the disproportionation `3HClO_(3)rarrHClO_(4)+Cl_(2)+2O_(2)+H_(2)O` the equivalent mass of the oxidising agent is (molar mass of `HClO_(4) = 84.45`)

A

16.89

B

32.22

C

84.45

D

28.15

Text Solution

Verified by Experts

The correct Answer is:
A

`ClO_(3)^(-) rarr Cl_2^(0)`
x - 6 = - 1 x = 0
x = +5 `" "` x = 0 [x = oxidation number]
Equivalent mass ` = ("Molecular mass")/("Oxidation number")`
`=(84.45)/5 = 16.89`
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