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For the redox reaction, MnO(4)^(-) + C...

For the redox reaction,
`MnO_(4)^(-) + C_(2)O_(4)^(2-) + H^(+) rarr Mn^(2+) + CO_(2) + H_(2)O`
the correct coefficients of the reactants for the balanced reaction are

A

`{:(MnO_4^(-),C_2O_4^(2-),H^(+)),(2,5,16):}`

B

`{:(MnO_4^(-),C_2O_4^(2-),H^(+)),(16,5,2):}`

C

`{:(MnO_4^(-),C_2O_4^(2-),H^(+)),(5,16,2):}`

D

`{:(MnO_4^(-),C_2O_4^(2-),H^(+)),(2,16,5):}`

Text Solution

Verified by Experts

The correct Answer is:
A
`MnO_(4)^(-)+8H^(+)+5e^(-)rarrMn^(2+)+4H_2Oxx2`
`(C_2O_4^(2-)rarr2CO_2+2e^(-)xx5)/(2MnO_(4)^(-)+5C_2O_4^(2+)+16H^(+)rarr2Mn^(2+)+10CO_2+8H_2O)`
Thus the coefficient of `MnO_4^(-) ,C_2O_4^(2-)` and `H^(+)` in the above balanced equation respectively are 2, 5, 16.
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