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The oxidation number of sulphur in Na2S4...

The oxidation number of sulphur in `Na_2S_4O_6` is .

A

`2/3`

B

`3/2`

C

0 and +5

D

`5/2`

Text Solution

Verified by Experts

The correct Answer is:
C
`Na_(2) S_(4) O_6`
`-2 (+1) +4a +6 (-2) =0 :. a = +5/2`
Here also, this value is the average oxidation number of S . The structure of `Na_2S_4O_6` is
`Na-O-underset(O)underset(darr)overset(O)overset(uarr)S-S-S-underset(O)underset(darr)overset(O)overset(uarr)S-O-Na`
Thus, oxidation number of each S atom forming coordinate bond is +5 , whereas oxidation number of each S atom involved in pure covalent bonding is zero.
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