In the balanced chemical reaction
`IO_(3)^(ө)+aI^(ө)+bH^(ө)rarrcH_(2)O+dI_(2)`
`a, b,c`, and `d`, respectively, correspond to

Options

A. 5, 6, 3, 3
B. 5, 3, 6, 3
C. 3, 5, 3, 6
D. 5, 6, 5, 5

Answer

A

Explanation

`IO_(3)^(-)+aI^(-)+bH^(+)rarrcH_2O+dI_2`
Step 1 : `I^(-1) rarrI_2` (oxidation)
`IO_(3)^(-) rarr I_2` (reduction)
Step 2 : `2IO_(3)^(-)+12H^(+) rarrI_2 +6H_2O`
Step 3: `2IO_3^(-)+12H^(+)+10e^(-)rarrI_2+6H_2O `
`2I^(-) rarr I_(2) + 2e^(-)`
Step 4 : `2IO_(3)^(-)+12H^(+) +10e^(-)rarrI_2 +6H_2O`
`[2I^(-) rarrI_2+2e^(-)]5`
Step 5 : `2IO_(3)^(-)+10I^(-) + 12H^(+)rarr6I_2+6H_2O`
`IO_3^(-) +5I^(-)+6H^(+)rarr3I_2 +3H_2O`
On comparing, a = 5, b = 6, c = 3, d = 3.