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The fraction of total volume occupied by...

The fraction of total volume occupied by the atom present in a simple cubic is

A

`pi/6`

B

`pi/(3sqrt(2))`

C

`pi/(4sqrt(2))`

D

`pi/4`

Text Solution

Verified by Experts

The correct Answer is:
A
`P.E. =("Vel.occupied the atom in a unit cell")/("vol. of unit cell") = (4/3 pir^(3))/a^(3)`
For simple unit `a = 2r = (4/3 pir^(3))/(8r^(3)) = (4pi)/24 = pi/6`
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Knowledge Check

  • The fraction of total volume occupied by the atoms present in a simple cube is

    A
    `pi/(3sqrt2)`
    B
    `pi/(4sqrt2)`
    C
    `pi/4`
    D
    `pi/6`

  • The fraction of total volume occupied by the atoms present in a simple cube is

    A
    `(pi)/(6)`
    B
    `(pi)/(3sqrt(2))`
    C
    `(pi)/(4sqrt(2))`
    D
    `(pi)/(4)`

  • The fraction of the total volume occupied by the atoms present in a simple cube is

    A
    `pi//4`
    B
    `pi//6`
    C
    `pi/3sqrt2`
    D
    pi/4sqrt2`