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The fraction of total volume occupied by...

The fraction of total volume occupied by the atom present in a simple cubic is

A

`pi/6`

B

`pi/(3sqrt(2))`

C

`pi/(4sqrt(2))`

D

`pi/4`

Text Solution

Verified by Experts

The correct Answer is:
A
`P.E. =("Vel.occupied the atom in a unit cell")/("vol. of unit cell") = (4/3 pir^(3))/a^(3)`
For simple unit `a = 2r = (4/3 pir^(3))/(8r^(3)) = (4pi)/24 = pi/6`
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