Home
Class 12
CHEMISTRY
The second order Bragg diffraction of X-...

The second order Bragg diffraction of X-rays with `lambda=1.0 Å` from a set of parallel planes in a metal occurs at an angle `60^(@)`. The distance between the scattering planes in the crystals is

A

0.575 A

B

1.00 A

C

2.00 A

D

1.15 A

Text Solution

Verified by Experts

The correct Answer is:
D

`2d sin theta = n lambda` or `2 xx d xx sin 60^(@) = 2 xx 1 A`
or `2 xx d xx 0.8660 = 2`
or `d = 1.15 A (sin 60^(@) = sqrt(3)//2` or 0.8660)
Promotional Banner

Topper's Solved these Questions

  • SOLID STATE

    ERRORLESS|Exercise NCERT BASED QUESTIONS (CRYSTAL STRUCTURE AND COORDINATION NUMBER) |20 Videos
  • SOLID STATE

    ERRORLESS|Exercise NCERT BASED QUESTIONS (DEFECTS IN CRYSTAL) |29 Videos
  • SOLID STATE

    ERRORLESS|Exercise NCERT BASED QUESTIONS (CRYSTAL PACKING)|10 Videos
  • POLYMERS

    ERRORLESS|Exercise ASSERTION & REASON|4 Videos
  • SOLUTIONS

    ERRORLESS|Exercise ASSERTION AND REASON|16 Videos

Similar Questions

Explore conceptually related problems

The second order Bragg diffraction of X rays with lambda=Å form a set of parallel planes in a metal occurs at an angle 60^(@) . the distance between the scattering planes in the crystal is

The first - order diffraction os X- rays from a certain set of crystal planes occurs an angle of 11.8^(@) from the planes. If the planes are 0.281 nm apart, what is the wavelength of X- rays?

Find the distance between the parallel planes x+y-z+4=0 and x+y-z+5=0

Normal form || Intercept form || Parallel plane || Distance OF a point from a plane || Distance between two parallel planes|| Equation OF bisector plane

The angle of diffraction 2 theta for a first - order nature was found to be 27^(@)8' using X- rays of wavelength 2.29Å . Calculate the distance between two diffracted planes.