A compound is compound by cation C and anion A. The anions hexagonal close packed (hcp) lattice and the cations occupy 75% of octahedral voids. The formula of the compound is

Options

A. `C_(4)A_(3)`
B. `C_(2)A_(3)`
C. `C_(3)A_(2)`
D. `C_(3)A_(4)`

Answer

D

Explanation

Number of A atoms in one unit cell = 6
Number of C atoms in one unit cell = `75/100 xx 6`
`= (3 xx 6)/4`
`C: A`
`= (3 xx 6)/4: 6 rArr 3 : 4`
`therefore C_(3)A_(4)`