The ionic radii of `A^(+) and B^(-)` ions are `0.98 xx 10^(-10) and 1.81 xx 10^(-10) m` .The coordinatyion number of each ion in `AB` is

Options

A. 6
B. 4
C. 8
D. 2

Answer

A

Explanation

Radii ratio `= r_(+)/r_(-) =(0.98 xx 10^(-10))/(1.81 xx 10^(-10)) = 0.54`
radii ratio is in between 0.414 to 0.732 so, coordination number is 6.