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A transition metal A has 'spin-only' mag...

A transition metal A has 'spin-only' magnetic moment value of 1.8 Bm. When it is reacted with dilute sulphuric acid in the presence of air, its compound B is formed. B reacts with compound C to give compound D with the liberation of iodine. Then the metal A and compounds B, C and D are respectively

A

`Ti, TiSO_4, KI and TiI_2`

B

`Zn , ZnSO_4 , KI and Zn_2I_2`

C

`Cu, CuSO_4, KI and Cu_2I_2`

D

`Cu, CuSO_4, KI and CuI_2`

Text Solution

Verified by Experts

The correct Answer is:
C
`underset(""A"")(Cu) + H_2SO_4 to underset(""B"") (CuSO_4) + H_2`
`underset(""B"")(CuSO_4 + underset(""C"")KI to CuI_2 + K_2SO_4`
`2CuI_2 to underset(""D"")(Cu_2I_2) + I_2`
On addition of KI solution in aqueous solution of `CuSO_4`, it produces yellow coloured solution of `CuI_2`, which is decomposed into white ppt. of `Cu_2I_2 and I_2`.
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