In aqueous solution `Cr^(2+)` is stronger reducing agent than `Fe^(2+)`. This is because

Options

A. `Cr(2+)`ion is more stable than `Fe^(2+)`
B. `Cr^(3+)` ion with `d^3` configuration has favourable crystal field stabilisation energy
C. `Cr^(3+)` has half-filled configuration and hence more stable
D. `Fe^(3+)` in aqueous solution is more stable than`Cr^(3+)`

Answer

B

Explanation

Half – filled `(t_(2g)^3)` configuration has favourable crystal field stabilizing energy. So `Cr^(2+)` can readily form `Cr^(3+)`, being a strong reducting agent.