Reaction of solid `KMnO_4` which conc. `H_2SO_4` produces manganese heptoxide `(Mn_2O_7)` in

Options

A. Solution state
B. Solid state
C. Fine powder
D. None of these

Explanation

To solve the question regarding the reaction of solid KMnO4 with concentrated H2SO4 to produce manganese heptoxide (Mn2O7), we can follow these steps:

### Step 1: Write the Reactants
The reactants in this reaction are solid potassium permanganate (KMnO4) and concentrated sulfuric acid (H2SO4).

### Step 2: Identify the Reaction
When KMnO4 is treated with concentrated H2SO4, it undergoes a dehydration reaction. The concentrated sulfuric acid acts as a dehydrating agent.

### Step 3: Write the Balanced Chemical Equation
The balanced chemical equation for the reaction is:
\[ 2 \text{KMnO}_4 + 3 \text{H}_2\text{SO}_4 \rightarrow \text{Mn}_2\text{O}_7 + K_2\text{SO}_4 + 3 \text{H}_2\text{O} \]
In this reaction, two moles of KMnO4 react with three moles of H2SO4 to produce one mole of manganese heptoxide (Mn2O7), one mole of potassium sulfate (K2SO4), and three moles of water (H2O).

### Step 4: Describe the Product
Manganese heptoxide (Mn2O7) is a red-brown liquid that is formed as a result of this reaction. It is important to note that Mn2O7 is a powerful oxidizing agent.

### Step 5: Conclusion
The reaction of solid KMnO4 with concentrated H2SO4 produces manganese heptoxide (Mn2O7) along with potassium sulfate and water.

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