Silverhalide which is readily soluble in ammonium hydroxide is

Options

A. Silver chloride
B. Silver bromide
C. Silver fluoride
D. Silver iodide

Explanation

To solve the question regarding which silver halide is readily soluble in ammonium hydroxide, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Silver Halides**: The silver halides in question are silver chloride (AgCl), silver bromide (AgBr), silver fluoride (AgF), and silver iodide (AgI).

2. **Understand Solubility in Ammonium Hydroxide**: Ammonium hydroxide (NH4OH) is a common reagent used to dissolve certain metal halides. We need to determine which of the silver halides can form a soluble complex with ammonium hydroxide.

3. **Examine Silver Chloride**: Silver chloride (AgCl) is known to form a soluble complex when treated with ammonium hydroxide. The reaction can be represented as:
\[ \text{AgCl} + 2 \text{NH}_4\text{OH} \rightarrow \text{[Ag(NH}_3\text{)}_2]^+\text{Cl}^- + 2 \text{H}_2\text{O} \]
This indicates that AgCl dissolves in ammonium hydroxide to form a soluble complex.

4. **Check Other Silver Halides**:
- **Silver Bromide (AgBr)**: It is less soluble in ammonium hydroxide compared to AgCl.
- **Silver Fluoride (AgF)**: It is generally soluble in water and does not significantly react with ammonium hydroxide.
- **Silver Iodide (AgI)**: It is insoluble in ammonium hydroxide.

5. **Conclusion**: Among the silver halides, silver chloride (AgCl) is the one that is readily soluble in ammonium hydroxide.

### Final Answer:
The silver halide that is readily soluble in ammonium hydroxide is **Silver Chloride (AgCl)**.