`AgCl` dissolved in excess of `NH_(3), KCN` and `Na_(2)S_(2)O_(3)` solutions the complex produces ions

Options

A. `[Ag(NH_3)_2]^(+), [Ag(CN)_2^(+) and [Ag(S_2O_3)_2]^(3-)`
B. `[Ag(NH_3)_2]^(2+) , [Ag(CN)_2]^(3-) and [Ag(S_2O_3)_2]^(2-)`
C. `[Ag(NH_3)_4]^(2+), [Ag(CN)_2]^(3-) and [Ag_2(S_2O_3)_2]^(2-)`
D. `[Ag(NH_3)_2]^(+) , [Ag(CN)_2]^(-) and [Ag(S_2O_3)_2]^(3-)`

Answer

D

Explanation

`AgCl + 2NH_4 OH to [Ag(NH_3)_2]Cl + 2H_2O`
`AgCL + 2KCN to K [Ag(CN)_2] + KCl `
`AgCl + 2KCN to K[Ag(CN)_2] + KCl `
`AgCl + Na_2S_2O_3 to Na_3 [Ag(S_2O_3)_2] + NaCl`……