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When calomel react with NH(4)OH solution...

When calomel react with `NH_(4)OH` solution the compound formed is

A

`NH_2 - Hg - Cl `

B

`Hg_2 Cl_2 NH_3`

C

`Hg (NH_3)_2 Cl_2`

D

`HgCl_2NH_3`

Text Solution

Verified by Experts

The correct Answer is:
A
`underset(("Calomel"))(Hg_2Cl_2 overset(NH_4OH)to Hg + NH_2 - Hg - Cl + NH_4 Cl`.
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