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The calculated spin only magnetic moment...

The calculated spin only magnetic moment of `Cr^2+` ion is:

A

3.87 BM

B

4.90 BM

C

5.92 BM

D

2.84 BM

Text Solution

Verified by Experts

The correct Answer is:
B

Electronic configuration of `Cr - [Ar] 3d^5 4 s^1`
Electronic configuration of `Cr^(2+) - [Ar]3d^4`
Number of unpaired `e^(-) = 4`
Spin only magnetic moment ` = sqrt(n (n + 2))`
Spin only magnetic moment `e^(-)`
Spin only magnetic moment ` = sqrt(4 (4 + 2))`
`sqrt24 BM`
` = 4.9 BM`
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