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molality, molarity, mole fraction...

molality, molarity, mole fraction

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Earlier the concept of equivalent weight was very common and the concentrations of the solutions were expressed in terms of normolities. The convenience was that the substances reacted in the ratio of their gram equivalents. So there was no need for writing the balanced equations to determine the amounts of the substances reacted. However, determination of equivalent weights posed difficulty in certain cases. Moreover, the equivalent weight of the same substance is not same in different reactions. For example, KMnO_(4) has different equivalent weight in the basic medium than in teh acidic medium. Hence, now-a-days, mole concept is more common and the concentrations of the solutions are generally expressed in terms of molarities, though some other methods like molality, molarity, mole fractions etc. are also used The mole fraction of hydrochloric acid in the solution will be

Earlier the concept of equivalent weight was very common and the concentrations of the solutions were expressed in terms of normolities. The convenience was that the substances reacted in the ratio of their gram equivalents. So there was no need for writing the balanced equations to determine the amounts of the substances reacted. However, determination of equivalent weights posed difficulty in certain cases. Moreover, the equivalent weight of the same substance is not same in different reactions. For example, KMnO_(4) has different equivalent weight in the basic medium than in teh acidic medium. Hence, now-a-days, mole concept is more common and the concentrations of the solutions are generally expressed in terms of molarities, though some other methods like molality, molarity, mole fractions etc. are also used The molality of the above solution will be nearly

The density of a 10.0% by mass of KCl solution in water is 1.06 g/mL. Calculate molarity, molality and mole fraction of KCl in the solution.

When 0.575 xx 10^(-2) kg of Glaube's salt is dissolved in water, we get 1 dm^(3) of a solution of density 1077.2 kg m^(-3) . Calculate the molarity, molality, and mole fraction of Na_(2)SO_(4) in the solution.

8.0575xx10^(-2) kg of Glauber's slat is dissolved in water to obtain 1 dm^(3) of a solution of density 1077.2 kg m^(-3) . Calculate the molarity, molality and mole fraction of Na_(2)SO_(4) in solution.

Assertion: For calculating the molality or the mole fraction of solute, if the molarity is known, it is necessary to know the density of the solution. Reason: Molality, molarity and the mole fraction of solute can be calculated from the weight percentage and the density of the solution.

Relation between molarity and molality|Mole fraction |Problem on mixing of solution

Concentration terms-W/W %,W/V %, Molarity,Molality,Mole Fraction ,PPb,PPm