The density of the nucleus is

Options

A. `2.4xx10^(15)kgm^(-3)`
B. `2.4xx10^(19)kgm^(-3)`
C. `2.4xx10^(17)kgm^(-3)`
D. `2.4xx10^(14)kgm^(-3)`

Answer

C

Explanation

`eta=A/(4/3piR^(3))`
Where,
`eta` = density of nucleus
A = mass number
`R=A^(1//3)R_(0)`
`R_(0)=1.25fm`
`eta=A/(4/3pi(A^(1//3)R_(0))^(3))=3/(4pi(1.25fm)^(3))`
= `1.22xx10^(44)m^(-3)`
The mass density is the product of n by the nuclear mass.
The calculated mass density, using a nucleon mass of
`1.67xx10^(-27)kg` is
`(1.67xx10^(-27)kg)(1.22xx10^(44)m^(-3))`
= `2.04xx10^(17)kg*m^(-3)`.