The frequency of an electromagnetic radiation is `2xx10^(6)Hz`. What is its wavelength in metres
(Velocity of light = `3xx10^(8)ms^(-1)`)

Options

A. `6.0xx10^(14)`
B. `1.5xx10^(4)`
C. `1.5xx10^(2)`
D. `0.66xx10^(-2)`

Explanation

To find the wavelength of the electromagnetic radiation given its frequency, we can use the formula that relates the speed of light (c), frequency (ν), and wavelength (λ):

\[ c = \nu \cdot \lambda \]

Where:
- \( c \) is the speed of light (in meters per second),
- \( \nu \) is the frequency (in hertz),
- \( \lambda \) is the wavelength (in meters).

We can rearrange this formula to solve for wavelength (λ):

\[ \lambda = \frac{c}{\nu} \]

### Step-by-Step Solution:

1. **Identify the given values**:
- Frequency (ν) = \( 2 \times 10^6 \) Hz
- Speed of light (c) = \( 3 \times 10^8 \) m/s

2. **Substitute the values into the formula**:
\[ \lambda = \frac{3 \times 10^8 \, \text{m/s}}{2 \times 10^6 \, \text{Hz}} \]

3. **Perform the division**:
- First, divide the coefficients:
\[ \frac{3}{2} = 1.5 \]
- Next, divide the powers of ten:
\[ \frac{10^8}{10^6} = 10^{8-6} = 10^2 \]
- Combine the results:
\[ \lambda = 1.5 \times 10^2 \, \text{m} \]

4. **Final result**:
\[ \lambda = 150 \, \text{m} \]

### Answer:
The wavelength of the electromagnetic radiation is \( 150 \, \text{m} \).