The specific charge of a proton is 9.6 x...

The specific charge of a proton is `9.6 xx 10^7 C kg^-1`, then for and `alpha-"particles"` it will be.

`38.4xx10^(7)Ckg^(-1)`

`19.2xx10^(7)Ckg^(-1)`

`2.4xx10^(7)Ckg^(-1)`

`4.8xx10^(7)Ckg^(-1)`

Text Solution

Verified by Experts

The correct Answer is:

`(q/m)_(alpha)=1/2(q/m)_(p)=1/2xx9.6xx10^(7)=4.8xx10^(7)Ckg^(-1)`.

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