If the ionization energy for the hydrogen atom is 13.6 eV , the energy required to excite it from the ground state to the next higher state is nearly

Options

A. `1.69xx10^(-20)J`
B. `1.69xx10^(-23)J`
C. `1.69xx10^(23)J`
D. `1.69xx10^(25)J`

Answer

B

Explanation

`E=(-13.6)/n^(2)=(-13.6)/4=-3.4eV//"atom"`
We know that energy required for excitation
`DeltaE=E_(2)-E_(1)=-3.4-(-13.6)=10.2eV`
Therefore energy required for excitation of electron per atom
= `10.2/(6.02xx10^(23))=1.69xx10^(-23)J`.