If the radius of the drogen atom is 53 p...

If the radius of the drogen atom is 53 pm, the radius of the `He^(+)` ion is closest to :

108 pm

81 pm

27 pm

13 pm

Text Solution

Verified by Experts

The correct Answer is:

`r_(He^(o+))=r_(H)xxn^(2)/Z`
`r_(He^(+))=53xx1/2=26.5`pm
It is closest to 27 pm.

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