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Calculate de Broglie wavelength of an el...

Calculate de Broglie wavelength of an electron travelling at `1 %` of the speed of light.

A

`2.73xx10^(-24)m`

B

`2.42xx10^(-10)m`

C

`242.2xx10^(10)m`

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
B
One percent of the speed of light is
`v=(1/100)(3.00xx10^(8)ms^(-1))=3.00xx10^(6)ms^(-1)`
Momentum of the electron (p) = mv
= `(9.11xx10^(-31)kg)(3.00xx10^(6)ms^(-1))`
= `2.73xx10^(-24)kgms^(-1)`
The de-Broglie wavelength of this electron is
`lamda=h/p=(6.626xx10^(-34))/(2.73xx10^(-24)kgms^(-1))`
`lamda=2.424xx10^(-10)m`
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