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A

`5,0,0,+1/2`

B

`5,1,0,+1/2`

C

`5,1,1,+1/2`

D

`6,0,0,+1/2`

Text Solution

Verified by Experts

The correct Answer is:
A

Electronic configuration of `Rb_((37))` is
`1s^(2)2s^(2)2p^(6)3s^(2)3p^(6)3d^(10)4s^(2)4p^(6)5s^(1)`
So for the valence shell electron `(5s^(1))`
`n=5,l=0,m=0,s=+1/2`.
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