The total number of electrons present in all `s` orbitals, all the `p` orbitals, and all the `d` orbitals of cesium ion are, respectively,

Options

A. `8,26,10`
B. `10,24,20`
C. `8,22,24`
D. `12,20,22`

Answer

B

Explanation

`(Cs_(55))=1s^(2),2s^(2),2p^(6),3s^(2),3p^(6),3d^(10),4s^(2),4p^(6),4d^(10),5s^(2),5p^(6),6s^(1)`
`Cs^(+)=1s^(2),2s^(2),2p^(6),3s^(2),3p^(6),3d^(10),4s^(2),4p^(6),4d^(10),5s^(2),5p^(6)`
Total no. of `e^(-)` in s-orbitals = 10
Total no. of `e^(-)` in p-orbitals = 24
Total no. of `e^(-)` in d-orbitals = 20.