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Calculate the energy in joule correspond...

Calculate the energy in joule corresponding to light of wavelength 45 nm (Planck.s constant `h=6.63xx10^(-34)` Js, speed of light `c=3xx10^(8) ms^(-1))`

A

`4.42xx10^(-15)J`

B

`4.42xx10^(-18)J`

C

`6.67xx10^(15)J`

D

`6.67xx10^(11)J`

Text Solution

Verified by Experts

The correct Answer is:
B
`E=(hc)/lamda=(6.63xx10^(-34)xx3xx10^(8))/(45xx10^(-9))`
= `4.42xx10^(-18)J`.
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