The value of Planck's constant is `6.63 xx 10^(-34)Js`. The velocity of light is `3.0 xx 10^(8)ms^(-1)`. Which value is closest to the wavelength in nanometers of a quantum of light with frequency `8xx10^(15)s^(-1)`?

Options

A. `3xx10^(7)`
B. `2xx10^(-25)`
C. `5xx10^(-18)`
D. `4xx10^(1)`

Answer

D

Explanation

`lamda=c/v=(3xx10^(8))/(8xx10^(15))=3.75xx10^(-8)`
= `3.75xx10^(-8)xx10^(9)nm=4xx10^(1)nm`