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The orbital angular momentum of a p-ele...

The orbital angular momentum of a p-electron is given as :

A

`h/(sqrt2pi)`

B

`sqrt3h/(2pi)`

C

`sqrt(3/2)h/pi`

D

`sqrt6*h/(2pi)`

Text Solution

Verified by Experts

The correct Answer is:
A
Orbital angular momentum = `h/(2pi)sqrt(l(l+1))`
l = 1
So = `h/(2pi)sqrt2=h/(sqrt2pi)`.
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