The electronic configuration of four elements `L, P, Q` and `R` are given in brackets
`L (1s^(2), 2s^(2), 2p^(4)) , P (1s^(2), 2p^(6), 3s^(1))`
`Q (1s^(2), 2s^(2)2p^(6), 3s^(2)3p^(5)), R (1s^(2), 2s^(2)2p^(6), 3s^(2))`
The formula of ionic compounds that can be formed between elements are

Options

A. `L_2 P , RL, PQ and R_2 Q`
B. `LP, RL, PQ and RQ`
C. `P_2L, RL, PQ and RQ_2`
D. `LP, R_2L , P_2 Q and RQ`

Answer

C

Explanation

Valencies of L, Q, P and R is -2, -1, +1 and +2 respectively so they will form `P_2 L, RL, PQ and RQ_2`.