In the given bonds which one is most ionic

Options

A. `Cs - Cl`
B. `Al - Cl`
C. `C - Cl`
D. `H - Cl`

Explanation

To determine which bond is the most ionic among the given options (C-S, C-Cl, H-Cl), we need to follow these steps:

### Step 1: Understand Ionic Character
Ionic character in a bond is primarily determined by the difference in electronegativity between the two atoms involved in the bond. The greater the difference, the more ionic the bond is.

### Step 2: Identify Electronegativity Values
We need to look up the electronegativity values for the elements involved:
- Carbon (C): 2.5
- Sulfur (S): 2.5
- Chlorine (Cl): 3.0
- Hydrogen (H): 2.1

### Step 3: Calculate Electronegativity Differences
Now, we can calculate the electronegativity differences for each bond:
- C-S: |2.5 - 2.5| = 0
- C-Cl: |2.5 - 3.0| = 0.5
- H-Cl: |2.1 - 3.0| = 0.9

### Step 4: Compare the Differences
Now we compare the electronegativity differences:
- C-S: 0
- C-Cl: 0.5
- H-Cl: 0.9

### Step 5: Determine the Most Ionic Bond
The bond with the highest electronegativity difference is H-Cl (0.9), indicating that it is the most ionic bond among the options provided.

### Conclusion
Therefore, the bond that is most ionic is **H-Cl**.

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