The electronic configuration of the outer most shell of the most electronegative element is :

Options

A. `2s^2 2p^5`
B. `3s^2 3p^5`
C. `4s^2 4p^5`
D. `5s^2 2p^5`

Answer

A

Explanation

The electronic configuration represents
`2s^2 2p^5` = fluorine = most electronegative element
`3s^2 3p^5` = chlorine
`4s^2 4p^5` = bromine
`5s^2 5p^5` = iodine