In `XeF_(6)`, oxidation state and of hybridisation of Xe and shape of the molecule are, respectively

Options

A. ` + 6, sp^3 d^3`, distorted octahedral
B. ` + 4, sp^3 d^2`, square planar
C. ` + 6, sp^3`, pyramidal
D. ` + 6, sp^3 d^2`, square pyramidal

Answer

A

Explanation

Oxidation state of Xe in `XeF_6` is +6.
In the formation of `XeF_6, sp^3 d^3` hybridisation occurs which gives the molecule a pentagonal bipyramidal structure. Six positions are occupied by fluorine atoms and one position is occupied by a lone pair of electrons. Due to presence of lone pair, distortion in structure takes place. The actual structure is distorted octahedral.