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SF2, SF4 and SF6 have the hybridizations...

`SF_2, SF_4 and SF_6` have the hybridizations at sulphur atom respectively, as

A

`sp^2, sp^3, sp^2 d^2`

B

`sp^3, sp^3, sp^3d^2`

C

`sp^3, sp^3 d , sp^3 d^2`

D

`sp^3, spd^2, d62 sp^3`

Text Solution

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The correct Answer is:
To determine the hybridization of the sulfur atom in SF2, SF4, and SF6, we will follow these steps: ### Step 1: Analyze SF2 1. **Count the Valence Electrons**: Sulfur has 6 valence electrons, and each fluorine contributes 1 electron. For SF2, we have: - 6 (from S) + 2 (from 2 F) = 8 total valence electrons. 2. **Determine Bonds and Lone Pairs**: In SF2, sulfur forms 2 single bonds with fluorine atoms. This uses 2 of the 6 valence electrons, leaving: - 6 - 2 = 4 electrons, which means there are 2 lone pairs remaining on sulfur. 3. **Calculate the Steric Number**: The steric number is the sum of sigma bonds and lone pairs: - Steric number = 2 (sigma bonds) + 2 (lone pairs) = 4. 4. **Determine Hybridization**: A steric number of 4 corresponds to sp³ hybridization. ### Step 2: Analyze SF4 1. **Count the Valence Electrons**: For SF4: - 6 (from S) + 4 (from 4 F) = 10 total valence electrons. 2. **Determine Bonds and Lone Pairs**: In SF4, sulfur forms 4 single bonds with fluorine atoms. This uses 4 of the 6 valence electrons, leaving: - 6 - 4 = 2 electrons, which means there is 1 lone pair remaining on sulfur. 3. **Calculate the Steric Number**: The steric number is: - Steric number = 4 (sigma bonds) + 1 (lone pair) = 5. 4. **Determine Hybridization**: A steric number of 5 corresponds to sp³d hybridization. ### Step 3: Analyze SF6 1. **Count the Valence Electrons**: For SF6: - 6 (from S) + 6 (from 6 F) = 12 total valence electrons. 2. **Determine Bonds and Lone Pairs**: In SF6, sulfur forms 6 single bonds with fluorine atoms. This uses all 6 of the valence electrons, leaving: - 6 - 6 = 0 electrons, which means there are no lone pairs remaining on sulfur. 3. **Calculate the Steric Number**: The steric number is: - Steric number = 6 (sigma bonds) + 0 (lone pairs) = 6. 4. **Determine Hybridization**: A steric number of 6 corresponds to sp³d² hybridization. ### Final Answer - The hybridizations of sulfur in SF2, SF4, and SF6 are: - SF2: sp³ - SF4: sp³d - SF6: sp³d²

To determine the hybridization of the sulfur atom in SF2, SF4, and SF6, we will follow these steps: ### Step 1: Analyze SF2 1. **Count the Valence Electrons**: Sulfur has 6 valence electrons, and each fluorine contributes 1 electron. For SF2, we have: - 6 (from S) + 2 (from 2 F) = 8 total valence electrons. 2. **Determine Bonds and Lone Pairs**: In SF2, sulfur forms 2 single bonds with fluorine atoms. This uses 2 of the 6 valence electrons, leaving: - 6 - 2 = 4 electrons, which means there are 2 lone pairs remaining on sulfur. ...
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